20x^2+8x=148

Solution for 20x^2+8x=148 equation:

20x^2+8x=148

We move all terms to the left:

20x^2+8x-(148)=0

a = 20; b = 8; c = -148;
Δ = b2-4ac
Δ = 82-4·20·(-148)
Δ = 11904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11904}=\sqrt{64*186}=\sqrt{64}*\sqrt{186}=8\sqrt{186}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{186}}{2*20}=\frac{-8-8\sqrt{186}}{40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{186}}{2*20}=\frac{-8+8\sqrt{186}}{40}
$